anyone know how to do this question?
haha
lets do it~
2eu = 1 + (5v+u)(2e+1) - 5v
2eu = 1 + 10ve + 5v + 2ue + u -5V
0 = 1 + love + 5v + 2e + u - 5v - 2eu
= 1 + love + u
is unique huh?
but love is troublesome sometime~
everyone seem getting trouble in it~
good luck all~
:)
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